Home Reactions Blog
Language: ru es en
Chemiday Log in:

The reaction between the oxide of niobium(V) and dithiobiurea with the formation of oxitrichloride of niobium(V) oxide sulphur(IV) and sulfur

2Nb2O5 + 6S2Cl2 → 4NbOCl3 + 3SO2 + 9S

[ Check the balance ]
The reaction between the oxide of niobium(V) and dithiobiurea with the formation of oxitrichloride of niobium(V) oxide sulphur(IV) and sulfur.

poiskFind another reaction
Thermodynamic properties Thermodynamic properties of substances
Table of solubility The solubility of the substances
Periodic Table Periodic table of elements

Picture of reaction: img1 BB html

Сoding to search: 2 Nb2O5 + 6 S2Cl2 = 4 NbOCl3 + 3 SO2 + 9 S

Add / Edited: 12.12.2019 /

Evaluation of information: 0.0 out of 5 / number of votes: 0

Please register to post comments
ChemiDay you always could choose go nuts or keep calm with us or without.
About | Feedback and suggestions | Contact us | Author
ChemiDay.com © 2023
Cookies policy, User agreement, Privacy policy.