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The reaction between sulphide of lanthanum and bromoiodide with the formation of bromide of lanthanum and hydrogen sulfide

La2S3 + 6HBr → 2LaBr3 + 3H2S




The reaction between sulphide of lanthanum and bromoiodide with the formation of bromide of lanthanum and hydrogen sulfide.


Picture of reaction: img1 BB html

Сoding to search: La2S3 + 6 HBr = 2 LaBr3 + 3 H2S

Add / Edited: 16.12.2019 /

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