Home Reactions Blog
Language: ru es en
Chemiday Log in:

The reaction between sulphide of lanthanum and bromoiodide with the formation of bromide of lanthanum and hydrogen sulfide

La2S3 + 6HBr → 2LaBr3 + 3H2S

[ Check the balance ]
The reaction between sulphide of lanthanum and bromoiodide with the formation of bromide of lanthanum and hydrogen sulfide.

poiskFind another reaction
Thermodynamic properties Thermodynamic properties of substances
Table of solubility The solubility of the substances
Periodic Table Periodic table of elements

Picture of reaction: img1 BB html

Сoding to search: La2S3 + 6 HBr = 2 LaBr3 + 3 H2S

Add / Edited: 16.12.2019 /

Evaluation of information: 0.0 out of 5 / number of votes: 0

Please register to post comments
ChemiDay you always could choose go nuts or keep calm with us or without.
About | Feedback and suggestions | Contact us | Author
Хостинг от uWebChemiDay.com © 2025
Cookies policy, User agreement, Privacy policy.