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Bromine(III) fluoride react with tin(IV) fluoride

2BrF3 + SnF4 → (BrF2)2[SnF6]

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Bromine(III) fluoride react with tin(IV) fluoride to produce hexafluorostannate(IV) difluorobromine(III).

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Сoding to search: 2 BrF3 + SnF4 = BrF22SnF6

Add / Edited: 26.12.2014 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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