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Silver(I) fluoride react with boron trifluoride

AgF + BF3 → Ag[BF4]

Silver(I) fluoride react with boron trifluoride to produce tetrafluoroborate silver(I). This reaction takes place at a temperature of <200°C.

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Picture of reaction: img1 BB html

Сoding to search: AgF + BF3 = AgBF4 { AgBF4 }

Add / Edited: 16.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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