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Gold(III) chloride react with iron(II) sulfate
AuCl
3
+ 3FeSO
4
Au + Fe
2
(SO
4
)
3
+ FeCl
3
[ Check the balance ]
Gold(III) chloride react with iron(II) sulfate to produce gold, iron(III) sulfate and iron(III) chloride. This reaction takes place at a temperature near 200°C.
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Picture of reaction:
Сoding to search:
AuCl3 + 3 FeSO4 cnd [ temp ] = Au + Fe2SO43 + FeCl3
Add / Edited:
24.01.2015 /
Evaluation of information:
5.0 out of 5 / number of votes: 1
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