H[AuCl4] + N2H5Cl = Au + N2 + HCl |

4H[AuCl₄] + 3N₂H₅Cl → 4Au + 3N₂ + 19HCl

Hydrogen tetrachloridoaurate(III) react with hydrazinium chloride to produce gold, nitrogen and hydrogen chloride. The reaction takes place in a boiling solution.

As a result, reaction is produced colloid gold.

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Hydrogen tetrachloridoaurate(III) react with hydrazinium chloride

4H[AuCl₄] + 3N₂H₅Cl → 4Au + 3N₂ + 19HCl

Picture of reaction:

Сoding to search: 4 HAuCl4 + 3 N2H5Cl = 4 Au + 3 N2 + 19 HCl

Add / Edited: 24.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Hydrogen tetrachloridoaurate(III) react with hydrazinium chloride

4H[AuCl4] + 3N2H5Cl → 4Au + 3N2 + 19HCl

Picture of reaction:

Сoding to search: 4 HAuCl4 + 3 N2H5Cl = 4 Au + 3 N2 + 19 HCl

Add / Edited: 24.01.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

4H[AuCl₄] + 3N₂H₅Cl → 4Au + 3N₂ + 19HCl

Add / Edited: 24.01.2015 /