B + NaOH + H2O = Na[B(OH)4] + H2 |

2B + 2NaOH + 6H₂O → 2Na[B(OH)₄] + 3H₂

Boron react with sodium hydroxide and water to produce sodium tetrahydroxoborate(III) and hydrogen. Boron is amorphous. Sodium hydroxide - concentrated solution.

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Boron react with sodium hydroxide and water

2B + 2NaOH + 6H₂O → 2Na[B(OH)₄] + 3H₂

Picture of reaction:

Сoding to search: 2 B + 2 NaOH + 6 H2O = 2 NaBOH4 + 3 H2

Add / Edited: 25.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Boron react with sodium hydroxide and water

2B + 2NaOH + 6H2O → 2Na[B(OH)4] + 3H2

Picture of reaction:

Сoding to search: 2 B + 2 NaOH + 6 H2O = 2 NaBOH4 + 3 H2

Add / Edited: 25.01.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

2B + 2NaOH + 6H₂O → 2Na[B(OH)₄] + 3H₂

Add / Edited: 25.01.2015 /