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Boron react with hydrogen fluoride

2B + 6HF → 2BF3 + 3H2

[ Check the balance ]
Boron react with hydrogen fluoride to produce boron trifluoride(III) and hydrogen. This reaction takes place at a temperature of 400-500°C.

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Сoding to search: 2 B + 6 HF cnd [ temp ] = 2 BF3 + 3 H2

Add / Edited: 25.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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