Home Reactions Blog
Language: ru es en
Chemiday Log in:

Boron(III) bromide react with sulfuric acid

2BBr3 + 3H2SO4 → 2H3BO3 + 3Br2 + 3SO2

Boron(III) bromide react with sulfuric acid to produce orthoboric acid, bromine and sulfur dioxide. Sulfuric acid - concentrated solution. The reaction takes place in a boiling solution.

Picture of reaction: img1 BB html

Сoding to search: 2 BBr3 + 3 H2SO4 = 2 H3BO3 + 3 Br2 + 3 SO2

Add / Edited: 25.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Please register to post comments
ChemiDay you always could choose go nuts or keep calm with us or without.
About | Feedback and suggestions | Contact us | Author
Хостинг от uWebChemiDay.com © 2024
Cookies policy, User agreement, Privacy policy.