BBr3 + H2SO4 = H3BO3 + Br2 + SO2 |

2BBr₃ + 3H₂SO₄ → 2H₃BO₃ + 3Br₂ + 3SO₂

Boron(III) bromide react with sulfuric acid to produce orthoboric acid, bromine and sulfur dioxide. Sulfuric acid - concentrated solution. The reaction takes place in a boiling solution.

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Boron(III) bromide react with sulfuric acid

2BBr₃ + 3H₂SO₄ → 2H₃BO₃ + 3Br₂ + 3SO₂

Picture of reaction:

Сoding to search: 2 BBr3 + 3 H2SO4 = 2 H3BO3 + 3 Br2 + 3 SO2

Add / Edited: 25.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Boron(III) bromide react with sulfuric acid

2BBr3 + 3H2SO4 → 2H3BO3 + 3Br2 + 3SO2

Picture of reaction:

Сoding to search: 2 BBr3 + 3 H2SO4 = 2 H3BO3 + 3 Br2 + 3 SO2

Add / Edited: 25.01.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

2BBr₃ + 3H₂SO₄ → 2H₃BO₃ + 3Br₂ + 3SO₂

Add / Edited: 25.01.2015 /