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Boron(III) bromide react with sodium hydroxide
4BBr
3
+ 14NaOH → Na
2
B
4
O
7
+ 12NaBr + 7H
2
O
[ Check the balance ]
Boron(III) bromide react with sodium hydroxide to produce sodium tetraborate, sodium bromide and water. Sodium hydroxide - diluted solution.
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Picture of reaction:
Сoding to search:
4 BBr3 + 14 NaOH = Na2B4O7 + 12 NaBr + 7 H2O
Add / Edited:
25.01.2015 /
Evaluation of information:
5.0 out of 5 / number of votes: 1
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