B4C + TiO2 + C = TiB2 + CO |

B₄C + 2TiO₂ + 3C 2TiB₂ + 4CO

Boron carbide react with oxide titanium(IV) and carbon (coke) to produce boride titanium(II) and carbon monoxide. This reaction takes place at a temperature of over 2000°C.

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Boron carbide react with oxide titanium(IV) and carbon (coke)

B₄C + 2TiO₂ + 3C 2TiB₂ + 4CO

Picture of reaction:

Сoding to search: B4C + 2 TiO2 + 3 C cnd [ temp ] = 2 TiB2 + 4 CO

Add / Edited: 25.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Boron carbide react with oxide titanium(IV) and carbon (coke)

B4C + 2TiO2 + 3C 2TiB2 + 4CO

Picture of reaction:

Сoding to search: B4C + 2 TiO2 + 3 C cnd [ temp ] = 2 TiB2 + 4 CO

Add / Edited: 25.01.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

B₄C + 2TiO₂ + 3C 2TiB₂ + 4CO

Add / Edited: 25.01.2015 /