Home Reactions Blog
Language: ru es en
Chemiday Log in:

Boron(III) chloride react with sodium hydroxide

BCl3 + 4NaOH → Na[B(OH)4] + 3NaCl


Boron(III) chloride react with sodium hydroxide to produce sodium tetrahydroxoborate(III) and sodium chloride. Sodium hydroxide - concentrated solution.


Picture of reaction: img1 BB html

Сoding to search: BCl3 + 4 NaOH = NaBOH4 + 3 NaCl

Add / Edited: 25.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


Please register to post comments
ChemiDay you always could choose go nuts or keep calm with us or without.
About | Feedback and suggestions | Contact us | Author
Хостинг от uWebChemiDay.com © 2024
Cookies policy, User agreement, Privacy policy.