Home Reactions Blog
Language: ru es en
Chemiday Log in:

Boron(III) chloride react with ammonia

BCl3 + 4NH3 → BN + 3NH4Cl

Boron(III) chloride react with ammonia to produce boron(III) nitride and ammonium chloride. This reaction takes place at a temperature of 500-1000°C, in a flow H2.

Picture of reaction: img1 BB html

Сoding to search: BCl3 + 4 NH3 cnd [ temp ] = BN + 3 NH4Cl

Add / Edited: 25.01.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Please register to post comments
ChemiDay you always could choose go nuts or keep calm with us or without.
About | Feedback and suggestions | Contact us | VK page
ChemiDay.com © 2022
Cookies policy, User agreement, Privacy policy.