BF3 + LiH = B2H6 + Li[BF4] |

8BF₃ + 6LiH B₂H₆ + 6Li[BF₄]

Boron(III) fluoride react with lithium hydride to produce diborane and lithium tetrafluoroborate(III). This reaction takes place at a temperature near 35°C, in the medium of ester.

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Boron(III) fluoride react with lithium hydride

8BF₃ + 6LiH B₂H₆ + 6Li[BF₄]

Picture of reaction:

Сoding to search: 8 BF3 + 6 LiH cnd [ temp ] = B2H6 + 6 LiBF4

Add / Edited: 26.01.2015 /

Evaluation of information: 3.0 out of 5 / number of votes: 2

Boron(III) fluoride react with lithium hydride

8BF3 + 6LiH B2H6 + 6Li[BF4]

Picture of reaction:

Сoding to search: 8 BF3 + 6 LiH cnd [ temp ] = B2H6 + 6 LiBF4

Add / Edited: 26.01.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

8BF₃ + 6LiH B₂H₆ + 6Li[BF₄]

Add / Edited: 26.01.2015 /