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Sodium tetrafluoroborate(III) react with boron trioxide(III) and sulfuric acid
6Na[BF
4
] + B
2
O
3
+ 6H
2
SO
4
→ 8BF
3
+ 6NaHSO
4
+ 3H
2
O
[ Check the balance ]
Sodium tetrafluoroborate(III) react with boron trioxide(III) and sulfuric acid to produce boron trifluoride(III), sodium bisulfate and water. Sulfuric acid - concentrated solution.
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Picture of reaction:
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6 NaBF4 + B2O3 + 6 H2SO4 = 8 BF3 + 6 NaHSO4 + 3 H2O
Add / Edited:
31.01.2015 /
Evaluation of information:
5.0 out of 5 / number of votes: 1
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