Mg3B2 + H3PO4 = B4H10 + Mg3(PO4)2 + H2 |

2Mg₃B₂ + 4H₃PO₄ → B₄H₁₀ + 2Mg₃(PO₄)₂ + H₂

Magnesium boride react with phosphoric acid to produce tetraborane, magnesium phosphate and hydrogen. This reaction takes place at a temperature of no more 10°C.

Find another reaction

Thermodynamic properties of substances

The solubility of the substances

Periodic table of elements

Magnesium boride react with phosphoric acid

2Mg₃B₂ + 4H₃PO₄ → B₄H₁₀ + 2Mg₃(PO₄)₂ + H₂

Picture of reaction:

Сoding to search: 2 Mg3B2 + 4 H3PO4 = B4H10 + 2 Mg3PO42 + H2

Add / Edited: 03.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Magnesium boride react with phosphoric acid

2Mg3B2 + 4H3PO4 → B4H10 + 2Mg3(PO4)2 + H2

Picture of reaction:

Сoding to search: 2 Mg3B2 + 4 H3PO4 = B4H10 + 2 Mg3PO42 + H2

Add / Edited: 03.02.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

2Mg₃B₂ + 4H₃PO₄ → B₄H₁₀ + 2Mg₃(PO₄)₂ + H₂

Add / Edited: 03.02.2015 /