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The thermal decomposition of boron phosphide

4BP → P4 + 4B

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The thermal decomposition of boron phosphide to produce phosphorus and boron. This reaction takes place at a temperature of over 2000°C.

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Сoding to search: 4 BP cnd [ temp ] = P4 + 4 B

Add / Edited: 03.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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