B2S3 + HNO3 = H3BO3 + H2SO4 + NO2 + H2O |

B₂S₃ + 24HNO₃ → 2H₃BO₃ + 3H₂SO₄ + 24NO₂ + 6H₂O

Boron sulfide react with nitric acid to produce orthoboric acid, sulfuric acid, nitrogen dioxide and water. Nitric acid - concentrated solution. The reaction takes place in a boiling solution.

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Boron sulfide react with nitric acid

B₂S₃ + 24HNO₃ → 2H₃BO₃ + 3H₂SO₄ + 24NO₂ + 6H₂O

Picture of reaction:

Сoding to search: B2S3 + 24 HNO3 = 2 H3BO3 + 3 H2SO4 + 24 NO2 + 6 H2O

Add / Edited: 04.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Boron sulfide react with nitric acid

B2S3 + 24HNO3 → 2H3BO3 + 3H2SO4 + 24NO2 + 6H2O

Picture of reaction:

Сoding to search: B2S3 + 24 HNO3 = 2 H3BO3 + 3 H2SO4 + 24 NO2 + 6 H2O

Add / Edited: 04.02.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

B₂S₃ + 24HNO₃ → 2H₃BO₃ + 3H₂SO₄ + 24NO₂ + 6H₂O

Add / Edited: 04.02.2015 /