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Boron sulfide react with sodium hydroxide

B2S3 + 8NaOH → 2Na[B(OH)4] + 3Na2S

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Boron sulfide react with sodium hydroxide to produce sodium tetrahydroxoborate(III) and sodium sulfide. Sodium hydroxide - concentrated solution.

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Сoding to search: B2S3 + 8 NaOH = 2 NaBOH4 + 3 Na2S

Add / Edited: 04.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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