(NH4)2[BeF4] + NaOH = Na2[Be(OH)4] + NH3 • H2O + NaF |

(NH₄)₂[BeF₄] + 6NaOH → Na₂[Be(OH)₄] + 2(NH₃•H₂O) + 4NaF

Ammonium tetrafluoroberyllate(II) react with sodium hydroxide to produce sodium tetrahydroxoberyllate(II), ammonium hydroxide and sodium fluoride. Sodium hydroxide - concentrated solution.

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Ammonium tetrafluoroberyllate(II) react with sodium hydroxide

(NH₄)₂[BeF₄] + 6NaOH → Na₂[Be(OH)₄] + 2(NH₃•H₂O) + 4NaF

Picture of reaction:

Сoding to search: NH42BeF4 + 6 NaOH = Na2BeOH4 + 2 NH3 • H2O + 4 NaF

Add / Edited: 14.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Ammonium tetrafluoroberyllate(II) react with sodium hydroxide

(NH4)2[BeF4] + 6NaOH → Na2[Be(OH)4] + 2(NH3•H2O) + 4NaF

Picture of reaction:

Сoding to search: NH42BeF4 + 6 NaOH = Na2BeOH4 + 2 NH3 • H2O + 4 NaF

Add / Edited: 14.02.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

(NH₄)₂[BeF₄] + 6NaOH → Na₂[Be(OH)₄] + 2(NH₃•H₂O) + 4NaF

Add / Edited: 14.02.2015 /