Be(OH)2 + CH3COOH = [Be4(CH3COO)6O] + H2O |

Be(OH)₂ + CH₃COOH → [Be₄(CH₃COO)₆O] + 7H₂O

Beryllium hydroxide react with acetic acid to produce oxohexaacetoberyllium(II) and water. Acetic acid anhydrous. This reaction takes place in the medium of ester.

Find another reaction

Thermodynamic properties of substances

The solubility of the substances

Periodic table of elements

Beryllium hydroxide react with acetic acid

Be(OH)₂ + CH₃COOH → [Be₄(CH₃COO)₆O] + 7H₂O

Picture of reaction:

Сoding to search: BeOH2 + CH3COOH = Be4CH3COO6O + 7 H2O

Add / Edited: 15.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Beryllium hydroxide react with acetic acid

Be(OH)2 + CH3COOH → [Be4(CH3COO)6O] + 7H2O

Picture of reaction:

Сoding to search: BeOH2 + CH3COOH = Be4CH3COO6O + 7 H2O

Add / Edited: 15.02.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

Be(OH)₂ + CH₃COOH → [Be₄(CH₃COO)₆O] + 7H₂O

Add / Edited: 15.02.2015 /