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Bismuth(III) bromide react with sulfuric acid
4BiBr
3
+ 12H
2
SO
4
→ 2Bi
2
(SO
4
)
3
+ 6Br
2
+ 6SO
2
+ 12H
2
O
[ Check the balance ]
Bismuth(III) bromide react with sulfuric acid to produce bismuth(III) sulfate, bromine, sulfur dioxide and water. Sulfuric acid - concentrated solution.
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Picture of reaction:
Сoding to search:
4 BiBr3 + 12 H2SO4 = 2 Bi2SO43 + 6 Br2 + 6 SO2 + 12 H2O
Add / Edited:
16.02.2015 /
Evaluation of information:
5.0 out of 5 / number of votes: 1
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