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Lead(IV) oxide react with sodium oxide

PbO2 + 2Na2O → Na4PbO4

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Lead(IV) oxide react with sodium oxide to produce sodium orthoplumbate. This reaction takes place at a temperature near 400°C, in vacuo or in the atmosphere inert protective gas.

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Сoding to search: PbO2 + 2 Na2O cnd [ temp ] = Na4PbO4

Add / Edited: 17.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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