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Bismuth(III) iodide react with sodium hydroxide
BiI
3
+ 2NaOH ⇄ BiOI + 2NaI + H
2
O
[ Check the balance ]
Bismuth(III) iodide react with sodium hydroxide to produce bismuth(III) oxide-iodide, sodium iodide and water. Sodium hydroxide - concentrated solution.
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BiI3 + 2 NaOH = BiOI + 2 NaI + H2O
Add / Edited:
17.02.2015 /
Evaluation of information:
5.0 out of 5 / number of votes: 1
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