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Berkelium(IV) oxide react with hydrogen

2BkO2 + H2 → Bk2O3 + H2O

Berkelium(IV) oxide react with hydrogen to produce oxide berkelium(III) and water. This reaction takes place at a temperature near 600°C.

Picture of reaction: img1 BB html

Сoding to search: 2 BkO2 + H2 cnd [ temp ] = Bk2O3 + H2O

Add / Edited: 23.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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