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Boron react with water

2B + 3H2O «→» B2O3 + 3H2




Boron react with water to produce boron trioxide(III) and hydrogen. This reaction takes place at a temperature of 700-800°C.


Picture of reaction: img1 BB html

Сoding to search: 2 B + 3 H2O cnd [ temp ] = B2O3 + 3 H2

Add / Edited: 29.09.2014 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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