CuI + H2SO4 = CuSO4 + I2 + H2S + H2O | Copper(I) iodide react with sulfuric acid

4CuI + 5H₂SO₄ → 4CuSO₄ + 2I₂ + H₂S + 4H₂O

Copper(I) iodide react with sulfuric acid to produce copper sulfate, iodine, hydrogen sulfide and water. Sulfuric acid - concentrated heated solution.

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Copper(I) iodide react with sulfuric acid

4CuI + 5H₂SO₄ → 4CuSO₄ + 2I₂ + H₂S + 4H₂O

Picture of reaction:

Сoding to search: 4 CuI + 5 H2SO4 = 4 CuSO4 + 2 I2 + H2S + 4 H2O

Add / Edited: 08.04.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Copper(I) iodide react with sulfuric acid

4CuI + 5H2SO4 → 4CuSO4 + 2I2 + H2S + 4H2O

Picture of reaction:

Сoding to search: 4 CuI + 5 H2SO4 = 4 CuSO4 + 2 I2 + H2S + 4 H2O

Add / Edited: 08.04.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

4CuI + 5H₂SO₄ → 4CuSO₄ + 2I₂ + H₂S + 4H₂O

Add / Edited: 08.04.2015 /