CuI + KOH = Cu2O + KI + H2O | Copper(I) iodide react with potassium hydroxide

2CuI + 2KOH → Cu₂O + 2KI + H₂O

Copper(I) iodide react with potassium hydroxide to produce copper(I) oxide, potassium iodide and water. Potassium hydroxide - concentrated heated solution.

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Copper(I) iodide react with potassium hydroxide

2CuI + 2KOH → Cu₂O + 2KI + H₂O

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Сoding to search: 2 CuI + 2 KOH = Cu2O + 2 KI + H2O

Add / Edited: 08.04.2015 /

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Copper(I) iodide react with potassium hydroxide

2CuI + 2KOH → Cu2O + 2KI + H2O

Picture of reaction:

Сoding to search: 2 CuI + 2 KOH = Cu2O + 2 KI + H2O

Add / Edited: 08.04.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

2CuI + 2KOH → Cu₂O + 2KI + H₂O

Add / Edited: 08.04.2015 /