CuI + H2SO4 + MnO2 = CuSO4 + MnSO4 + I2 + H2O |

2CuI + 4H₂SO₄ + 2MnO₂ 2CuSO₄ + 2MnSO₄ + I₂ + 4H₂O

Copper(I) iodide react with sulfuric acid and manganese(IV) oxide to produce copper sulfate, manganese(II) sulfate, iodine and water. Sulfuric acid - concentrated solution. This reaction takes place at a temperature of 60-80°C.

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Copper(I) iodide react with sulfuric acid and manganese(IV) oxide

2CuI + 4H₂SO₄ + 2MnO₂ 2CuSO₄ + 2MnSO₄ + I₂ + 4H₂O

Picture of reaction:

Сoding to search: 2 CuI + 4 H2SO4 + 2 MnO2 cnd [ temp ] = 2 CuSO4 + 2 MnSO4 + I2 + 4 H2O

Add / Edited: 08.04.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Copper(I) iodide react with sulfuric acid and manganese(IV) oxide

2CuI + 4H2SO4 + 2MnO2 2CuSO4 + 2MnSO4 + I2 + 4H2O

Picture of reaction:

Сoding to search: 2 CuI + 4 H2SO4 + 2 MnO2 cnd [ temp ] = 2 CuSO4 + 2 MnSO4 + I2 + 4 H2O

Add / Edited: 08.04.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

2CuI + 4H₂SO₄ + 2MnO₂ 2CuSO₄ + 2MnSO₄ + I₂ + 4H₂O

Add / Edited: 08.04.2015 /