FeI2 + H2SO4 + H2O2 = Fe2(SO4)3 + I2 + H2O |

2FeI₂ + 3H₂SO₄ + 3H₂O₂ → Fe₂(SO₄)₃ + 2I₂ + 6H₂O

Iron(II) iodide react with sulfuric acid and hydrogen peroxide to produce iron(III) sulfate, iodine and water. Sulfuric acid - diluted solution. Hydrogen peroxide - concentrated solution.

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Iron(II) iodide react with sulfuric acid and hydrogen peroxide

2FeI₂ + 3H₂SO₄ + 3H₂O₂ → Fe₂(SO₄)₃ + 2I₂ + 6H₂O

Picture of reaction:

Сoding to search: 2 FeI2 + 3 H2SO4 + 3 H2O2 = Fe2SO43 + 2 I2 + 6 H2O

Add / Edited: 19.04.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Iron(II) iodide react with sulfuric acid and hydrogen peroxide

2FeI2 + 3H2SO4 + 3H2O2 → Fe2(SO4)3 + 2I2 + 6H2O

Picture of reaction:

Сoding to search: 2 FeI2 + 3 H2SO4 + 3 H2O2 = Fe2SO43 + 2 I2 + 6 H2O

Add / Edited: 19.04.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

2FeI₂ + 3H₂SO₄ + 3H₂O₂ → Fe₂(SO₄)₃ + 2I₂ + 6H₂O

Add / Edited: 19.04.2015 /