NaI + H2SO4 = I2 + H2S + NaHSO4 + H2O | Sodium iodide react with sulfuric acid

8NaI + 9H₂SO₄ 4I₂ + H₂S + 8NaHSO₄ + 4H₂O

Sodium iodide react with sulfuric acid to produce iodine, hydrogen sulfide, sodium bisulfate and water. Sulfuric acid - concentrated solution. This reaction takes place at a temperature of 30-50°C.

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Sodium iodide react with sulfuric acid

8NaI + 9H₂SO₄ 4I₂ + H₂S + 8NaHSO₄ + 4H₂O

Picture of reaction:

Сoding to search: 8 NaI + 9 H2SO4 cnd [ temp ] = 4 I2 + H2S + 8 NaHSO4 + 4 H2O

Add / Edited: 19.05.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Sodium iodide react with sulfuric acid

8NaI + 9H2SO4 4I2 + H2S + 8NaHSO4 + 4H2O

Picture of reaction:

Сoding to search: 8 NaI + 9 H2SO4 cnd [ temp ] = 4 I2 + H2S + 8 NaHSO4 + 4 H2O

Add / Edited: 19.05.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

8NaI + 9H₂SO₄ 4I₂ + H₂S + 8NaHSO₄ + 4H₂O

Add / Edited: 19.05.2015 /