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Iridium(III) chloride react with hydrogen sulfide

2IrCl3 + 4H2S → 2IrS2 + H2 + 6HCl

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Iridium(III) chloride react with hydrogen sulfide to produce iridium(IV) sulfide, hydrogen and hydrogen chloride. This reaction takes place by heating to the temperature of no more than 630°C.

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Сoding to search: 2 IrCl3 + 4 H2S cnd [ temp ] = 2 IrS2 + H2 + 6 HCl

Add / Edited: 31.05.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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