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Iridium(IV) chloride react with hydrogen sulfide

2IrCl4 + 4H2S → Ir2S3 + S + 8HCl

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Iridium(IV) chloride react with hydrogen sulfide to produce iridium(IV) sulfide, sulfur and hydrogen chloride. This reaction takes place at a temperature near 800°C.

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Сoding to search: 2 IrCl4 + 4 H2S cnd [ temp ] = Ir2S3 + S + 8 HCl

Add / Edited: 31.05.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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