Na3[IrCl6] + HNO3 + H2O = IrO2 + NO2 + NaNO3 + HCl |

Na₃[IrCl₆] + 4HNO₃ + H₂O → IrO₂ + NO₂ + 3NaNO₃ + 6HCl

Sodium hexachloridoiridate(III) react with nitric acid and water to produce iridium(IV) oxide, nitrogen dioxide, sodium nitrate and hydrogen chloride. Nitric acid - concentrated solution. The reaction takes place in a boiling solution.

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Sodium hexachloridoiridate(III) react with nitric acid and water

Na₃[IrCl₆] + 4HNO₃ + H₂O → IrO₂ + NO₂ + 3NaNO₃ + 6HCl

Picture of reaction:

Сoding to search: Na3IrCl6 + 4 HNO3 + H2O = IrO2 + NO2 + 3 NaNO3 + 6 HCl

Add / Edited: 31.05.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Sodium hexachloridoiridate(III) react with nitric acid and water

Na3[IrCl6] + 4HNO3 + H2O → IrO2 + NO2 + 3NaNO3 + 6HCl

Picture of reaction:

Сoding to search: Na3IrCl6 + 4 HNO3 + H2O = IrO2 + NO2 + 3 NaNO3 + 6 HCl

Add / Edited: 31.05.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

Na₃[IrCl₆] + 4HNO₃ + H₂O → IrO₂ + NO₂ + 3NaNO₃ + 6HCl

Add / Edited: 31.05.2015 /