Na3[IrCl6] + NaOH + O2 = IrO2 + NaCl + H2O |

4Na₃[IrCl₆] + 12NaOH + O₂ → 4IrO₂ + 24NaCl + 6H₂O

Sodium hexachloridoiridate(III) react with sodium hydroxide and oxygen to produce iridium(IV) oxide, sodium chloride and water. This reaction slowly takes place on air.

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Sodium hexachloridoiridate(III) react with sodium hydroxide and oxygen

4Na₃[IrCl₆] + 12NaOH + O₂ → 4IrO₂ + 24NaCl + 6H₂O

Picture of reaction:

Сoding to search: 4 Na3IrCl6 + 12 NaOH + O2 = 4 IrO2 + 24 NaCl + 6 H2O

Add / Edited: 01.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Sodium hexachloridoiridate(III) react with sodium hydroxide and oxygen

4Na3[IrCl6] + 12NaOH + O2 → 4IrO2 + 24NaCl + 6H2O

Picture of reaction:

Сoding to search: 4 Na3IrCl6 + 12 NaOH + O2 = 4 IrO2 + 24 NaCl + 6 H2O

Add / Edited: 01.06.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

4Na₃[IrCl₆] + 12NaOH + O₂ → 4IrO₂ + 24NaCl + 6H₂O

Add / Edited: 01.06.2015 /