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Iridium(IV) fluoride react with sodium hydroxide

IrF4 + 4NaOH → IrO2 + 4NaF + 2H2O

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Iridium(IV) fluoride react with sodium hydroxide to produce iridium(IV) oxide, sodium fluoride and water. Sodium hydroxide - diluted solution.

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Сoding to search: IrF4 + 4 NaOH = IrO2 + 4 NaF + 2 H2O

Add / Edited: 01.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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