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Iridium(IV) fluoride react with hydrogen

IrF4 + 2H2 → Ir + 4HF

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Iridium(IV) fluoride react with hydrogen to produce iridium and hydrogen fluoride. This reaction takes place at a temperature near 200°C.

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Сoding to search: IrF4 + 2 H2 cnd [ temp ] = Ir + 4 HF

Add / Edited: 01.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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