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Iridium(VI) fluoride react with iridium

2IrF6 + Ir → 3IrF4

Iridium(VI) fluoride react with iridium to produce iridium(IV) fluoride. This reaction takes place at a temperature of 100-120°C.

Picture of reaction: img1 BB html

Сoding to search: 2 IrF6 + Ir cnd [ temp ] = 3 IrF4

Add / Edited: 01.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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