IrO2 + Cl2 = IrCl3 + O2 |

2IrO₂ + 3Cl₂ 2IrCl₃ + 2O₂

Iridium(IV) oxide react with chlorine to produce iridium(III) chloride and oxygen. This reaction takes place at a temperature near 240°C initiated by the absorption of energy in the form of light.

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Iridium(IV) oxide react with chlorine

2IrO₂ + 3Cl₂ 2IrCl₃ + 2O₂

Picture of reaction:

Сoding to search: 2 IrO2 + 3 Cl2 cnd [ temp hν ] = 2 IrCl3 + 2 O2

Add / Edited: 01.06.2015 /

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Iridium(IV) oxide react with chlorine

2IrO2 + 3Cl2 2IrCl3 + 2O2

Picture of reaction:

Сoding to search: 2 IrO2 + 3 Cl2 cnd [ temp hν ] = 2 IrCl3 + 2 O2

Add / Edited: 01.06.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

2IrO₂ + 3Cl₂ 2IrCl₃ + 2O₂

Add / Edited: 01.06.2015 /