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Potassium iodide react with sulfuric acid

8KI + 9H2SO4 → 4I2 + H2S + 4H2O + 8KHSO4

Potassium iodide react with sulfuric acid to produce iodine, hydrogen sulfide, water and potassium bisulfate. Potassium iodide - solid. Sulfuric acid - concentrated solution. This reaction takes place at a temperature of 30-50°C.

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Сoding to search: 8 KI + 9 H2SO4 cnd [ temp ] = 4 I2 + H2S + 4 H2O + 8 KHSO4

Add / Edited: 05.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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