PbO2 + KI + HNO3 = I2 + Pb(NO3)2 + KNO3 + H2O |

PbO₂ + 2KI + 4HNO₃ → I₂ + Pb(NO₃)₂ + 2KNO₃ + 2H₂O

Lead(IV) oxide react with potassium iodide and nitric acid to produce iodine, lead(II) nitrate, potassium nitrate and water. Nitric acid - diluted solution. The reaction proceeds at room temperature.

Find another reaction

Thermodynamic properties of substances

The solubility of the substances

Periodic table of elements

Lead(IV) oxide react with potassium iodide and nitric acid

PbO₂ + 2KI + 4HNO₃ → I₂ + Pb(NO₃)₂ + 2KNO₃ + 2H₂O

Picture of reaction:

Сoding to search: PbO2 + 2 KI + 4 HNO3 = I2 + PbNO32 + 2 KNO3 + 2 H2O

Add / Edited: 05.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Lead(IV) oxide react with potassium iodide and nitric acid

PbO2 + 2KI + 4HNO3 → I2 + Pb(NO3)2 + 2KNO3 + 2H2O

Picture of reaction:

Сoding to search: PbO2 + 2 KI + 4 HNO3 = I2 + PbNO32 + 2 KNO3 + 2 H2O

Add / Edited: 05.06.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

PbO₂ + 2KI + 4HNO₃ → I₂ + Pb(NO₃)₂ + 2KNO₃ + 2H₂O

Add / Edited: 05.06.2015 /