K2MoO4 + KCN + HCl + K[BH4] = K4[Mo(CN)8] + H3BO3 + KCl + H2O |

4K₂MoO₄ + 32KCN + 25HCl + K[BH₄] → 4K₄[Mo(CN)₈] + H₃BO₃ + 25KCl + 13H₂O

Potassium molybdate react with potassium cyanide, hydrogen chloride and potassium tetrahydroborate to produce oktacyanomolybdate(IV) potassium, boric acid, potassium chloride and water. Hydrogen chloride - diluted solution.

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Potassium molybdate react with potassium cyanide, hydrogen chloride and potassium tetrahydroborate

4K₂MoO₄ + 32KCN + 25HCl + K[BH₄] → 4K₄[Mo(CN)₈] + H₃BO₃ + 25KCl + 13H₂O

Picture of reaction:

Сoding to search: 4 K2MoO4 + 32 KCN + 25 HCl + KBH4 = 4 K4MoCN8 + H3BO3 + 25 KCl + 13 H2O

Add / Edited: 06.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Potassium molybdate react with potassium cyanide, hydrogen chloride and potassium tetrahydroborate

4K2MoO4 + 32KCN + 25HCl + K[BH4] → 4K4[Mo(CN)8] + H3BO3 + 25KCl + 13H2O

Picture of reaction:

Сoding to search: 4 K2MoO4 + 32 KCN + 25 HCl + KBH4 = 4 K4MoCN8 + H3BO3 + 25 KCl + 13 H2O

Add / Edited: 06.06.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

4K₂MoO₄ + 32KCN + 25HCl + K[BH₄] → 4K₄[Mo(CN)₈] + H₃BO₃ + 25KCl + 13H₂O

Add / Edited: 06.06.2015 /