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Lead(II) acetate react with chlorine and sodium hydroxide

Pb(CH3COO)2 + Cl2 + 4NaOH → PbO2 + 2CH3COONa + 2NaCl + 2H2O

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Lead(II) acetate react with chlorine and sodium hydroxide to produce lead(IV) oxide, sodium acetate, sodium chloride and water.

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Сoding to search: PbCH3COO2 + Cl2 + 4 NaOH = PbO2 + 2 CH3COONa + 2 NaCl + 2 H2O

Add / Edited: 04.10.2014 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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