[Mo(CO)6] + HNO3 = MoO3 + CO2 + NO2 + H2O |

[Mo(CO)₆] + 18HNO₃ → MoO₃ + 6CO₂ + 18NO₂ + 9H₂O

Hexacarbonylmolybdenum react with nitric acid to produce molybdenum trioxide, carbon dioxide, nitrogen dioxide and water. Nitric acid - concentrated solution. The reaction takes place in a boiling solution.

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Hexacarbonylmolybdenum react with nitric acid

[Mo(CO)₆] + 18HNO₃ → MoO₃ + 6CO₂ + 18NO₂ + 9H₂O

Picture of reaction:

Сoding to search: MoCO6 + 18 HNO3 = MoO3 + 6 CO2 + 18 NO2 + 9 H2O

Add / Edited: 17.06.2015 /

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Hexacarbonylmolybdenum react with nitric acid

[Mo(CO)6] + 18HNO3 → MoO3 + 6CO2 + 18NO2 + 9H2O

Picture of reaction:

Сoding to search: MoCO6 + 18 HNO3 = MoO3 + 6 CO2 + 18 NO2 + 9 H2O

Add / Edited: 17.06.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

[Mo(CO)₆] + 18HNO₃ → MoO₃ + 6CO₂ + 18NO₂ + 9H₂O

Add / Edited: 17.06.2015 /