MoCl5 + CO + Al = [Mo(CO)6] + AlCl3 |

3MoCl₅ + 6CO + 5Al 3[Mo(CO)₆] + 5AlCl₃

Molybdenum(V) chloride react with carbon monoxide and aluminum to produce hexacarbonylmolybdenum and aluminum chloride. This reaction takes place in the medium of ester, at a temperature near 100°C and an overpressure.

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Molybdenum(V) chloride react with carbon monoxide and aluminum

3MoCl₅ + 6CO + 5Al 3[Mo(CO)₆] + 5AlCl₃

Picture of reaction:

Сoding to search: 3 MoCl5 + 6 CO + 5 Al cnd [ temp ] = 3 MoCO6 + 5 AlCl3

Add / Edited: 17.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Molybdenum(V) chloride react with carbon monoxide and aluminum

3MoCl5 + 6CO + 5Al 3[Mo(CO)6] + 5AlCl3

Picture of reaction:

Сoding to search: 3 MoCl5 + 6 CO + 5 Al cnd [ temp ] = 3 MoCO6 + 5 AlCl3

Add / Edited: 17.06.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

3MoCl₅ + 6CO + 5Al 3[Mo(CO)₆] + 5AlCl₃

Add / Edited: 17.06.2015 /