Na2B4O7 + C2H5OH + H2SO4 = B(C2H5O)3 + NaHSO4 + H2O |

Na₂B₄O₇ + 12C₂H₅OH + 2H₂SO₄ → 4B(C₂H₅O)₃ + 2NaHSO₄ + 7H₂O

Tetraborate sodium react with ethanol and sulfuric acid to produce ethoxide boron, sodium bisulfate and water. Sulfuric acid - concentrated solution. The reaction proceeds at room temperature.

Find another reaction

Thermodynamic properties of substances

The solubility of the substances

Periodic table of elements

Tetraborate sodium react with ethanol and sulfuric acid

Na₂B₄O₇ + 12C₂H₅OH + 2H₂SO₄ → 4B(C₂H₅O)₃ + 2NaHSO₄ + 7H₂O

Picture of reaction:

Сoding to search: Na2B4O7 + 12 C2H5OH + 2 H2SO4 = 4 BC2H5O3 + 2 NaHSO4 + 7 H2O

Add / Edited: 22.06.2015 /

Evaluation of information: 0.0 out of 5 / number of votes: 0

Tetraborate sodium react with ethanol and sulfuric acid

Na2B4O7 + 12C2H5OH + 2H2SO4 → 4B(C2H5O)3 + 2NaHSO4 + 7H2O

Picture of reaction:

Сoding to search: Na2B4O7 + 12 C2H5OH + 2 H2SO4 = 4 BC2H5O3 + 2 NaHSO4 + 7 H2O

Add / Edited: 22.06.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

Na₂B₄O₇ + 12C₂H₅OH + 2H₂SO₄ → 4B(C₂H₅O)₃ + 2NaHSO₄ + 7H₂O

Add / Edited: 22.06.2015 /