Na2B4O7 = B2O3 + NaBO2 |

Na₂B₄O₇ ⇄ B₂O₃ + 2NaBO₂

The thermal decomposition of sodium tetraborate to produce boron trioxide and sodium metaborate. This reaction takes place at a temperature of over 1575°C.

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The thermal decomposition of sodium tetraborate

Na₂B₄O₇ ⇄ B₂O₃ + 2NaBO₂

Picture of reaction:

Сoding to search: Na2B4O7 cnd [ temp ] = B2O3 + 2 NaBO2

Add / Edited: 22.06.2015 /

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The thermal decomposition of sodium tetraborate

Na2B4O7 ⇄ B2O3 + 2NaBO2

Picture of reaction:

Сoding to search: Na2B4O7 cnd [ temp ] = B2O3 + 2 NaBO2

Add / Edited: 22.06.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

Na₂B₄O₇ ⇄ B₂O₃ + 2NaBO₂

Add / Edited: 22.06.2015 /