Na2Cr2O7 + NaI + H2SO4 = Cr2(SO4)3 + I2 + Na2SO4 + H2O |

Na₂Cr₂O₇ + 6NaI + 7H₂SO₄ → Cr₂(SO₄)₃ + 3I₂ + 4Na₂SO₄ + 7H₂O

Sodium dichromate react with sodium iodide and sulfuric acid to produce chromium(III) sulfate, iodine, sodium sulfate and water. Sulfuric acid - diluted solution.

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Sodium dichromate react with sodium iodide and sulfuric acid

Na₂Cr₂O₇ + 6NaI + 7H₂SO₄ → Cr₂(SO₄)₃ + 3I₂ + 4Na₂SO₄ + 7H₂O

Picture of reaction:

Сoding to search: Na2Cr2O7 + 6 NaI + 7 H2SO4 = Cr2SO43 + 3 I2 + 4 Na2SO4 + 7 H2O

Add / Edited: 23.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Sodium dichromate react with sodium iodide and sulfuric acid

Na2Cr2O7 + 6NaI + 7H2SO4 → Cr2(SO4)3 + 3I2 + 4Na2SO4 + 7H2O

Picture of reaction:

Сoding to search: Na2Cr2O7 + 6 NaI + 7 H2SO4 = Cr2SO43 + 3 I2 + 4 Na2SO4 + 7 H2O

Add / Edited: 23.06.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

Na₂Cr₂O₇ + 6NaI + 7H₂SO₄ → Cr₂(SO₄)₃ + 3I₂ + 4Na₂SO₄ + 7H₂O

Add / Edited: 23.06.2015 /