NaH + B(C2H5O)3 = Na[BH4] + C2H5ONa |

4NaH + B(C₂H₅O)₃ → Na[BH₄] + 3C₂H₅ONa

Sodium hydride react with ethoxide boron to produce sodium tetrahydroxoborate(III) and sodium ethoxide. This reaction takes place at a temperature of 250-270°C ^[8,16].

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Sodium hydride react with ethoxide boron

4NaH + B(C₂H₅O)₃ → Na[BH₄] + 3C₂H₅ONa

Picture of reaction:

Сoding to search: 4 NaH + BC2H5O3 cnd [ temp ] = NaBH4 + 3 C2H5ONa

Add / Edited: 24.06.2015 /

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Sodium hydride react with ethoxide boron

4NaH + B(C2H5O)3 → Na[BH4] + 3C2H5ONa

Picture of reaction:

Сoding to search: 4 NaH + BC2H5O3 cnd [ temp ] = NaBH4 + 3 C2H5ONa

Add / Edited: 24.06.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

4NaH + B(C₂H₅O)₃ → Na[BH₄] + 3C₂H₅ONa

Add / Edited: 24.06.2015 /