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Silver(I) periodate react with chlorine and water

4Ag3IO5 + 6Cl2 + 10H2O → 4H5IO6 + 12AgCl + 3O2

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Silver(I) periodate react with chlorine and water to produce periodic acid, silver(I) chloride and oxygen.

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Сoding to search: 4 Ag3IO5 + 6 Cl2 + 10 H2O = 4 H5IO6 + 12 AgCl + 3 O2

Add / Edited: 24.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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